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	<title>Tips piratenkapern - История изменений</title>
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	<updated>2026-10-15T05:15:59Z</updated>
	<subtitle>История изменений этой страницы в вики</subtitle>
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	<entry>
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		<title>Maxim78: Новая страница: «2 dice Probabilities of throwing X skulls with two six-sided dice In words	In maths	Percentage Probability of no skulls	P(X = 0) = (⅚)²	≈ 69.4% Probability o...»</title>
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		<updated>2022-05-25T21:03:39Z</updated>

		<summary type="html">&lt;p&gt;Новая страница: «2 dice Probabilities of throwing X skulls with two six-sided dice In words	In maths	Percentage Probability of no skulls	P(X = 0) = (⅚)²	≈ 69.4% Probability o...»&lt;/p&gt;
&lt;p&gt;&lt;b&gt;Новая страница&lt;/b&gt;&lt;/p&gt;&lt;div&gt;2 dice&lt;br /&gt;
Probabilities of throwing X skulls with two six-sided dice&lt;br /&gt;
In words	In maths	Percentage&lt;br /&gt;
Probability of no skulls	P(X = 0) = (⅚)²	≈ 69.4%&lt;br /&gt;
Probability of one skull	P(X = 1) = 2 × (⅙) × (⅚)	≈ 27.8%&lt;br /&gt;
Probability of two skulls	P(X = 2) = (⅙)²	≈ 2.78%&lt;br /&gt;
8 dice&lt;br /&gt;
Probabilities of throwing X skulls with eight six-sided dice&lt;br /&gt;
In words	In maths	Percentage&lt;br /&gt;
Probability of no skulls	P(X = 0) = (⅚)⁸	≈ 23.3%&lt;br /&gt;
Probability of one skull	P(X = 1) = 8 × (⅙) × (⅚)⁷	≈ 37.2%&lt;br /&gt;
Probability of two skulls	P(X = 2) = 28 × (⅙)² × (⅚)⁶	≈ 26.0%&lt;br /&gt;
Probability of three skulls	P(X = 3) = 56 × (⅙)³ × (⅚)⁵	≈ 10.4%&lt;br /&gt;
Probability of four skulls	P(X = 4) = 70 × (⅙)⁴ × (⅚)⁴	≈ 2.60%&lt;br /&gt;
Probabilities of throwing X or more skulls with eight six-sided dice&lt;br /&gt;
In words	In maths	Percentage&lt;br /&gt;
Probability of one or more skulls	P(X ≥ 1)&lt;br /&gt;
= 1 − P(X = 0)&lt;br /&gt;
&lt;br /&gt;
= 1 − (⅚)⁸&lt;br /&gt;
&lt;br /&gt;
≈ 76.7%&lt;br /&gt;
Probability of two or more skulls	P(X ≥ 2)&lt;br /&gt;
= 1 − [ P(X = 0) + P(X = 1) ]&lt;br /&gt;
&lt;br /&gt;
= 1 − [ (⅚)⁸ + 8 × (⅙) × (⅚)⁷ ]&lt;br /&gt;
&lt;br /&gt;
≈ 39.5%&lt;br /&gt;
Probability of three or more skulls	P(X ≥ 3)&lt;br /&gt;
= 1 − [ P(X = 0) + P(X = 1) + P(X = 2) ]&lt;br /&gt;
&lt;br /&gt;
= 1 − [ (⅚)⁸ + 8 × (⅙) × (⅚)⁷ + 28 × (⅙)² × (⅚)⁶ ]&lt;br /&gt;
&lt;br /&gt;
≈ 13.5%&lt;br /&gt;
Probability of four or more skulls	P(X ≥ 4)&lt;br /&gt;
= 1 − [ P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) ]&lt;br /&gt;
&lt;br /&gt;
= 1 − [ (⅚)⁸ + 8 × (⅙) × (⅚)⁷ + 28 × (⅙)² × (⅚)⁶ + 56 × (⅙)³ × (⅚)⁵ ]&lt;br /&gt;
&lt;br /&gt;
≈ 3.07%&lt;/div&gt;</summary>
		<author><name>Maxim78</name></author>
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